(Need help) Beginner's question

[Sachin Raut]

Hi

I have a question in this following code.
<?php

class A

{

public $country;

function __construct($data=array())

{

if(!isset($data))

{

trigger_error("Couldn't construct address with a ".get_class());

}

}

}

$obj=new A();

?>

I am not sending any "array" as an argument while creating an object. And
hence "if statement" in constructor should have been executed, but it
displays blank page. My query is why it's not executing "if statement"?

Thanks
Sachin

[Stuart Dallas]

Post by Sachin Raut
Hi
I have a question in this following code.
<?php
class A
{
public $country;
function __construct($data=array())
{
if(!isset($data))
{
trigger_error("Couldn't construct address with a ".get_class());
}
}
}
$obj=new A();
?>
I am not sending any "array" as an argument while creating an object. And
hence "if statement" in constructor should have been executed, but it
displays blank page. My query is why it's not executing "if statement"?

You are giving it a default value of an empty array, therefore the variable
is set. Either change the default to null or change the !isset($data) to
simply !$data.

[Jigar Dhulla]

Hi,

$data will always be set. Check *if(empty($data)) *instead.

Post by Sachin Raut
Hi
I have a question in this following code.
<?php
class A
{
public $country;
function __construct($data=array())
{
if(!isset($data))
{
trigger_error("Couldn't construct address with a ".get_class());
}
}
}
$obj=new A();
?>
I am not sending any "array" as an argument while creating an object. And
hence "if statement" in constructor should have been executed, but it
displays blank page. My query is why it's not executing "if statement"?
Thanks
Sachin

[Domain nikha.org]

Post by Sachin Raut
Hi
I have a question in this following code.
<?php
class A
{
public $country;
function __construct($data=array())
{
if(!isset($data))
{
trigger_error("Couldn't construct address with a ".get_class());
}
}
}
$obj=new A();
?>
I am not sending any "array" as an argument while creating an object. And
hence "if statement" in constructor should have been executed, but it
displays blank page. My query is why it's not executing "if statement"?
Thanks
Sachin

Hi,
because $data is set! In your argument in the constructor: $data = array()!
try if(count($data) == 0)...
Niklaus

[Simon Schick]

Hi, Sachin

If you want your code to fail, you could set the default to NULL and check
for NULL.


<?php

class A

{

public $country;

function __construct($data=NULL)

{

if($data === NULL)

{

trigger_error("Couldn't construct address with a ".get_class());

}

}

}

$obj=new A();

?>

Bye,
Simon

Post by Sachin Raut
Hi
I have a question in this following code.
<?php
class A
{
public $country;
function __construct($data=array())
{
if(!isset($data))
{
trigger_error("Couldn't construct address with a ".get_class());
}
}
}
$obj=new A();
?>
I am not sending any "array" as an argument while creating an object. And
hence "if statement" in constructor should have been executed, but it
displays blank page. My query is why it's not executing "if statement"?
Thanks
Sachin