How to keep $_POST value when I have 3 submit options?

[Negin Nickparsa]

I have items showing up in list view or grid view.
I have 2 buttons List and Grid
and Items will show up in Grid view and List view
also I order them in a select tag by price and other options

when I sort by name I want to remember the state of view
whether it is grid or if it is list

user selects Grid view and then wants to order them by price. but when they
order by price booom!(submitted) they will go to default view which was
List view.It is not correct so bad.

I have an event onchange that when I click on selection the form will be
submitted
I want to keep the values so that it can remember whether it should sort
the items in grid view or list view

the live example can be seen here:

http://www.lenmar.com/general-purpose/aa/aa/nickel-metal-hydride/nickel-metal-hydride-battery

this is the older version which is working with Get method but the test
server is with $_POST I am showing the concept to help clarifying the
problem

as far as I attempted, I got the hidden values for $_POST
and then I pass them to the form but it still has problem
here is the sample code:


<form method="post" action="" id="myform">
<div id="gridSort">
<input type="hidden" name="selected_sort" value="<?php echo
!empty($_POST['sort']) ? strip_tags($_POST['sort']) : ''; ?>" />
<input type="hidden" name="selectionList_view" value="<?php echo
!empty($_POST['Listview']) ? strip_tags($_POST['Listview']) : ''; ?>" />
<input type="hidden" name="selectionGrid_view" value="<?php echo
!empty($_POST['Gridview']) ? strip_tags($_POST['Gridview']) : ''; ?>" />
<span>View Results As:</span> <span>
<input type="submit" class="listButtons" name="Lisview" value="List">
</span> <span>
<input type="submit" class="resultButtons" name="Gridview"
value="Grid"></span>
<select id="sortSelect" class="sortSelect" size="1" name="sort"
onchange="this.form.submit();" >
<option selected>Sort</option>
<option value="Name">Name</option>
<option value="PriceLowToHigh">Price - Low</option>
<option value="PriceHighToLow">Price - High</option>
</select>
</div>
</form>
<script type="text/javascript">
document.getElementById('sortSelect').value ="<?php if(!
$_POST['sort']):?>"Sort"<?php else: echo $_POST['sort']; endif;?>";
</script>
<pre>
<?php print_r($_POST); ?>
</pre>


I select the price high to low or something else I want it to remember what
I had chosen before that list? or grid?

my question is that is it possible to have just 1 form and submit and keep
them? hidden field didn't work as I tested.

Any help would be appreciated.

Sincerely
Negin Nickparsa

[Jeffry Killen]

Post by Negin Nickparsa
I have items showing up in list view or grid view.
I have 2 buttons List and Grid
and Items will show up in Grid view and List view
also I order them in a select tag by price and other options
when I sort by name I want to remember the state of view
whether it is grid or if it is list
user selects Grid view and then wants to order them by price. but when they
order by price booom!(submitted) they will go to default view which was
List view.It is not correct so bad.

How does the user designate the view he wants to see?
It appears that there must be a way, via javascript ajax call*
, to tell the server
initially what the preferred view is, so when the page reloads the
correct view
is displayed.

*or get/post sent to the page that is being viewed. I would do this as
<?php
// in the top of the page being viewed.

$_file_self = basename($_SERVER['PHP_SELF']);
$_view = '';
if($_GET['view'])
{
$_view = $_GET['view'];
}
?>

The

<a href="<?php print $_file_self ?>?view=grid">Grid View</a>
<a href="<?php print $_file_self ?>?view=list">List View</a>

You may also want to save the view preference as a session variable
or have code write a preference file for the user.
Is the user required to have an account? If so, include a variable that
designates the default view preference.

Post by Negin Nickparsa
I have an event onchange that when I click on selection the form will be
submitted
I want to keep the values so that it can remember whether it should sort
the items in grid view or list view
http://www.lenmar.com/general-purpose/aa/aa/nickel-metal-hydride/nickel-metal-hydride-battery
this is the older version which is working with Get method but the test
server is with $_POST I am showing the concept to help clarifying the
problem
as far as I attempted, I got the hidden values for $_POST
and then I pass them to the form but it still has problem
<form method="post" action="" id="myform">
<div id="gridSort">
<input type="hidden" name="selected_sort" value="<?php echo
!empty($_POST['sort']) ? strip_tags($_POST['sort']) : ''; ?>" />
<input type="hidden" name="selectionList_view" value="<?php echo
!empty($_POST['Listview']) ? strip_tags($_POST['Listview']) : ''; ?

" />

<input type="hidden" name="selectionGrid_view" value="<?php echo
!empty($_POST['Gridview']) ? strip_tags($_POST['Gridview']) : ''; ?

" />

<span>View Results As:</span> <span>
<input type="submit" class="listButtons" name="Lisview" value="List">
</span> <span>
<input type="submit" class="resultButtons" name="Gridview"
value="Grid"></span>
<select id="sortSelect" class="sortSelect" size="1" name="sort"
onchange="this.form.submit();" >
<option selected>Sort</option>
<option value="Name">Name</option>
<option value="PriceLowToHigh">Price - Low</option>
<option value="PriceHighToLow">Price - High</option>
</select>
</div>
</form>
<script type="text/javascript">
document.getElementById('sortSelect').value ="<?php if(!
$_POST['sort']):?>"Sort"<?php else: echo $_POST['sort']; endif;?>";
</script>
<pre>
<?php print_r($_POST); ?>
</pre>
I select the price high to low or something else I want it to
remember what
I had chosen before that list? or grid?
my question is that is it possible to have just 1 form and submit and keep
them? hidden field didn't work as I tested.
Any help would be appreciated.
Sincerely
Negin Nickparsa

[Negin Nickparsa]

Sincerely
Negin Nickparsa

Post by Negin Nickparsa
I have items showing up in list view or grid view.

Post by Negin Nickparsa
I have 2 buttons List and Grid
and Items will show up in Grid view and List view
also I order them in a select tag by price and other options
when I sort by name I want to remember the state of view
whether it is grid or if it is list
user selects Grid view and then wants to order them by price. but when they
order by price booom!(submitted) they will go to default view which was
List view.It is not correct so bad.

How does the user designate the view he wants to see?
It appears that there must be a way, via javascript ajax call*
, to tell the server
initially what the preferred view is, so when the page reloads the correct
view
is displayed.
*or get/post sent to the page that is being viewed. I would do this as
<?php
// in the top of the page being viewed.
$_file_self = basename($_SERVER['PHP_SELF']);
$_view = '';
if($_GET['view'])
{
$_view = $_GET['view'];
}
?>
The
<a href="<?php print $_file_self ?>?view=grid">Grid View</a>
<a href="<?php print $_file_self ?>?view=list">List View</a>
You may also want to save the view preference as a session variable
or have code write a preference file for the user.
Is the user required to have an account? If so, include a variable that
designates the default view preference.
​using get method can be a way to achieve it however I prefer to use post
method.

​can you give me hints about ajax parts? maybe I can do something with that.
for session they are so strict not using session for the sake of speed and
security.​

Post by Negin Nickparsa
​

Post by Negin Nickparsa
I have an event onchange that when I click on selection the form will be
submitted
I want to keep the values so that it can remember whether it should sort
the items in grid view or list view
http://www.lenmar.com/general-purpose/aa/aa/nickel-metal-
hydride/nickel-metal-hydride-battery
this is the older version which is working with Get method but the test
server is with $_POST I am showing the concept to help clarifying the
problem
as far as I attempted, I got the hidden values for $_POST
and then I pass them to the form but it still has problem
<form method="post" action="" id="myform">
<div id="gridSort">
<input type="hidden" name="selected_sort" value="<?php echo
!empty($_POST['sort']) ? strip_tags($_POST['sort']) : ''; ?>" />
<input type="hidden" name="selectionList_view" value="<?php echo
!empty($_POST['Listview']) ? strip_tags($_POST['Listview']) : ''; ?>" />
<input type="hidden" name="selectionGrid_view" value="<?php echo
!empty($_POST['Gridview']) ? strip_tags($_POST['Gridview']) : ''; ?>" />
<span>View Results As:</span> <span>
<input type="submit" class="listButtons" name="Lisview" value="List">
</span> <span>
<input type="submit" class="resultButtons" name="Gridview"
value="Grid"></span>
<select id="sortSelect" class="sortSelect" size="1" name="sort"
onchange="this.form.submit();" >
<option selected>Sort</option>
<option value="Name">Name</option>
<option value="PriceLowToHigh">Price - Low</option>
<option value="PriceHighToLow">Price - High</option>
</select>
</div>
</form>
<script type="text/javascript">
document.getElementById('sortSelect').value ="<?php if(!
$_POST['sort']):?>"Sort"<?php else: echo $_POST['sort']; endif;?>";
</script>
<pre>
<?php print_r($_POST); ?>
</pre>
I select the price high to low or something else I want it to remember what
I had chosen before that list? or grid?
my question is that is it possible to have just 1 form and submit and keep
them? hidden field didn't work as I tested.
Any help would be appreciated.
Sincerely
Negin Nickparsa

[Christoph Becker]

Post by Jeffry Killen
You may also want to save the view preference as a session variable
or have code write a preference file for the user.
Is the user required to have an account? If so, include a variable that
designates the default view preference.
​using get method can be a way to achieve it however I prefer to use post
method.

However, POST is not the right method in this case, see
<http://tools.ietf.org/html/rfc2616#section-9.1>.

​can you give me hints about ajax parts? maybe I can do something with that.
for session they are so strict not using session for the sake of speed and
security.​

Instead of a session, you could use a cookie or the browser's local
storage (the latter only, if you do not need to support old browsers).

[Jeffry Killen]

Post by Negin Nickparsa
Sincerely
Negin Nickparsa

Post by Negin Nickparsa
I have items showing up in list view or grid view.

Post by Negin Nickparsa
I have 2 buttons List and Grid
and Items will show up in Grid view and List view
also I order them in a select tag by price and other options
when I sort by name I want to remember the state of view
whether it is grid or if it is list
user selects Grid view and then wants to order them by price. but
when
they
order by price booom!(submitted) they will go to default view
which was
List view.It is not correct so bad.

How does the user designate the view he wants to see?
It appears that there must be a way, via javascript ajax call*
, to tell the server
initially what the preferred view is, so when the page reloads the
correct
view
is displayed.
*or get/post sent to the page that is being viewed. I would do this
as
<?php
// in the top of the page being viewed.
$_file_self = basename($_SERVER['PHP_SELF']);
$_view = '';
if($_GET['view'])
{
$_view = $_GET['view'];
}
?>
The
<a href="<?php print $_file_self ?>?view=grid">Grid View</a>
<a href="<?php print $_file_self ?>?view=list">List View</a>
You may also want to save the view preference as a session variable
or have code write a preference file for the user.
Is the user required to have an account? If so, include a variable
that
designates the default view preference.
​using get method can be a way to achieve it however I prefer to
use post
method.

​can you give me hints about ajax parts? maybe I can do something
with that.
for session they are so strict not using session for the sake of
speed and
security.​

If your not familiar with javascript, doing it with ajax will be a
challenge.
Ajax is a method of sending ansyncronous calls to the server and
receiving
a reply. The page does not reload so if the reply contains string
content or
change of state in the client, you have to handle it with javascript
programming.
With ajax, also you will need a separate sever side script to handle
the request.
I have tried to use ajax with self processing forms and pages but
haven't been able
to master that.

Using get method I believe is the simplest. If you use post, you will
need a form
to submit as I understand it.

<form name="viewPref" name="viewPref" action="<?php print $_file_self?

Post by Negin Nickparsa
" method="post">

View Preference:<br>
Grid View <input type="radio" name="pref" id="grid" value="grid"><br>
List View <input type="radio" name="pref" id="list" value="list"><br>
<input type="submit" name="UserPrefs" value="Set Your View Preferences">
</form>

Notice the radio buttons both have the same name. You would look for
$_POST['pref'] and it will
have the value that the user selected. With the id values set you can
use javascript to apply specific
actions. I don't advise using text fields in the form because garbage
and spam can be submitted without
screening. All the elements in the page will have to have DIFFERENT id
values applied. Accept in
radio button and checkbox groups, all elements will also have to have
different names. The name and
id value of a single element can be the same (accept in radio and
checkbox groups).

Post by Negin Nickparsa

Post by Negin Nickparsa

Post by Negin Nickparsa
I have an event onchange that when I click on selection the form
will be
submitted
I want to keep the values so that it can remember whether it
should sort
the items in grid view or list view
http://www.lenmar.com/general-purpose/aa/aa/nickel-metal-
hydride/nickel-metal-hydride-battery
this is the older version which is working with Get method but the
test
server is with $_POST I am showing the concept to help clarifying
the
problem
as far as I attempted, I got the hidden values for $_POST
and then I pass them to the form but it still has problem
<form method="post" action="" id="myform">
<div id="gridSort">
<input type="hidden" name="selected_sort" value="<?php echo
!empty($_POST['sort']) ? strip_tags($_POST['sort']) : ''; ?>" />
<input type="hidden" name="selectionList_view" value="<?php echo
!empty($_POST['Listview']) ? strip_tags($_POST['Listview']) : ''; ?

" />

<input type="hidden" name="selectionGrid_view" value="<?php echo
!empty($_POST['Gridview']) ? strip_tags($_POST['Gridview']) : ''; ?

" />

<span>View Results As:</span> <span>
<input type="submit" class="listButtons" name="Lisview"
value="List">
</span> <span>
<input type="submit" class="resultButtons" name="Gridview"
value="Grid"></span>
<select id="sortSelect" class="sortSelect" size="1" name="sort"
onchange="this.form.submit();" >
<option selected>Sort</option>
<option value="Name">Name</option>
<option value="PriceLowToHigh">Price - Low</option>
<option value="PriceHighToLow">Price - High</option>
</select>
</div>
</form>
<script type="text/javascript">
document.getElementById('sortSelect').value ="<?php if(!
$_POST['sort']):?>"Sort"<?php else: echo $_POST['sort']; endif;?

";

</script>
<pre>
<?php print_r($_POST); ?>
</pre>
I select the price high to low or something else I want it to
remember
what
I had chosen before that list? or grid?
my question is that is it possible to have just 1 form and submit
and keep
them? hidden field didn't work as I tested.
Any help would be appreciated.
Sincerely
Negin Nickparsa